Question 842990
{{{b=12-2a}}};
-
{{{ab=a(12-2a)=3}}}
{{{12a-2a^2=3}}}
{{{-2a^2+12a-3=0}}}
{{{2a^2-12a+3=0}}}
-
-
{{{Discriminant=144-4*2*3=144-24}}}
{{{Discriminant=120}}}
-
{{{a=(12+- sqrt(120))/4}}}
{{{a=(12+- 2sqrt(30))/(2*2)}}}
{{{a=(6+- sqrt(30))/2}}}
{{{highlight(a=3+- (1/2)sqrt(30))}}}
-
Use the found values for a to find that of b.  Start with b=12-2a.  You COULD use ab=3 if you want; which way is YOUR choice.