Question 842769
How do you solve sec 3theta over 2 equals -2 with the interval [0,2pie]
{{{sec(3theta)/2=-2}}}
{{{sec(3theta)=-4}}}
{{{cos(3theta)=-1/4}}}
3theta=1.82 and 4.46 radians in quadrants II and III
theta=0.61 and 1.49 radians