Question 842649
h(2)=-9*2+1
h(2)=-17


{{{g/h(2)=(x-1)(x-6)/h(2)=-(x-1)(x-6)/17}}}.
The domain for this is all real numbers.


The domain for {{{g(x)/h(x)}}}?
{{{(x-1)(x-6)/(-9x+1)}}}.
Values of x NOT in the domain of g/h is only one value.
The ratio g/h cannot accept {{{-9x+1=0}}}
{{{-9x=-1}}}
{{{9x=1}}}
{{{highlight(x=1/9)}}}-------This is the value of x NOT in the domain of {{{g(x)/(h(x))}}}.