Question 842630
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Hi, Previously Posted
{{{2x^(-2/3) - 5x^(-1/3) - 3 = 0}}}
The Idea is to Let n = {{{x^(-1/3)}}}   
  2n^2 - 5n - 3 = 0
(2n+1)(n-3)= 0
  (2n+1)= 0, n = -1/2,  {{{x = 1/(-1/8) = -8}}}
0r (n-3)= 0, n = 3 ,    x = 1/27 
n = {{{1/x^(1/3)}}} , n^3 = 1/x (Cubing both sides)    0r x = 1/n^3