Question 842542
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Hi
x^2 &#8722; 6x + 6 = 0     |Form:  ax^2 + bx + c
using the Quadratic Equation
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
{{{x = (6 +- sqrt( 36-24 ))/(2) }}} 
{{{x = (6 +- sqrt( 12 ))/(2) }}} 
{{{x = (6 +- sqrt( 4*3))/(2) }}}
 {{{x = (6 +- 2sqrt( 3))/(2) }}}
 {{{x = 3+- sqrt( 3) }}}
 x is  {{{3+ sqrt( 3)}}}, {{{3- sqrt( 3)}}}