Question 842431
{{{(6-i)/(3+i)=((6-i)/(3+i))*((3-i)/(3-i))=(6-i)*(3-i)/((3+i)*(3-i))=(18-6i-3i+i^2)/(3^2-i^2)=(18-9i-1)/(9+1)=(17-9i)/10=1.7-0.9i}}}