Question 842476
{{{32/2=16}}};
{{{32/3=10&2/3}}};
{{{32/4=8}}}.


Three boxes must distribute these 32 doughnuts.  .
Start with 10 and 12.  That would be 22 doughnuts.  Another with 8 will finish the 32.  That is about the best way to distribute these 32 doughnuts.
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Boxes each for 8, 10, 12 doughnuts



ANOTHER TRY
16+12=28, and then third box to contain 4.
This is not as neat as the first described combination.


ANOTHER
14+12=26 and then third box to contain 6.
Still not as uniform as the first described combination.