Question 9356
lol it is just an exercise in semantics to be honest...


ok, let x triangle y = {{{x^2 + xy + y^2}}}. I shall write this as follows, for ease of writing:


xTy = {{{x^2 + xy + y^2}}}


so... when you see 2T5 for example, you look at the definition, which says xTy ie x=2 and y=5 and you put these values into the equation as stated, namely the {{{x^2 + xy + y^2}}}


so, to your question... What is the value of: (3 triangle 1) triangle 1? Well, we have brackets, so we have to do the thing inside the bracket first...so


3T1 means x=3, y=1 in {{{x^2 + xy + y^2}}}, giving {{{(3)^2 + (3)(1) + (1)^2}}} which is 9 + 3 + 1 --> 13.


And now, from (3T1)T1 we have 13T1, where x=13 and y=1, so {{{(13)^2 + (13)(1) + (1)^2}}} which is 169 + 13 + 1 which gives 183.


Hope it isn't so "mind-blowing" now and possibly may even be considered easy?


jon.