Question 842076
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Hi,
Green Lines denote z = -.5  and z = .5 on the Standard Normal Curve
{{{drawing(400,200,-5,5,-.5,1.5, graph(400,200,-5,5,-.5,1.5, exp(-x^2/2)), green(line(.5,0,.5,exp(-.5^2/2)),line(-.5,0,-.5,exp(-.5^2/2))),locate(4.8,-.01,z),locate(4.8,.2,z))}}}
P(z &#8804; .5) = .6915    
a)P (0 &#8804; Z &#8804; .5) = .6915 - .5 = .1915
 b)P (Z &#8804; .5) = .6915
 c)P (Z &#8804; -.5) = .5-.1915
 d)P (Z >.5) = 1- .6915
 e)P (-.5 &#8804; Z &#8804; .5) = 2(.1915)