Question 842109
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Hi,
"I differentiated y = e^x (which is e^x), which gives you your gradient for the tangent"(line)
{{{highlight_green(m)}}} = e^x and when x = 0 &#8658; {{{highlight_green(m)}}} = 1
The "tangent to the curve is a LINE:  y-1 = {{{highlight_green(1)}}}(x-0)  0r y = x + 1
{{{drawing(300,300,   -6, 6, -6, 6, grid(1), 
circle(0, 1,0.2),
graph( 300, 300, -6, 6, -6, 6,0, e^x, x+1))}}}