Question 842043
{{{2y^2+4xy=x^2}}}
{{{2y^2+4xy-x^2=0}}}


{{{y=(-4x+- sqrt(16x^2-4*2*(-x^2)))/(2*2)}}}
{{{y=(-4x+- sqrt(16x^2+8x^2))/4}}}
{{{y=(-4x+- x*sqrt(24))/4}}}
{{{y=(-4x+- 2x*sqrt(6))/4}}}
{{{y=(-x+- (1/2)x*sqrt(6))}}}
{{{highlight(y=-x(1+- (1/2)sqrt(6)))}}}