Question 841864
{{{-3 = (37-3n)^(1/2) - n}}}
{{{n-3 = (37-3n)^(1/2)}}}
{{{n^2-6n+9=37-3n}}}
{{{n^2-3n-28=0}}}

{{{(n-7)(n+4)=0}}}

Two possible solutions:
{{{n-7=0}}}
{{{n=7}}}
Checking:
{{{-3=(37-21)^(1/2)-7}}}
{{{-3=4-7}}}
{{{3=-3}}}
True
and
{{{n+4=0}}}
{{{n=-4}}}
Checking:
{{{-3=(37+12)^(1/2)-4}}}
{{{-3=7-4}}}
{{{-3=3}}}
False,  not a solution.
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.
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{{{n=7}}}