Question 841926
The entire left side as an absolute value could be treated as a variable. It MUST be positive, being an absolute value, and it is.  The right hand member is positive 5.


You know |2x-1| is positive, but you must allow for 2x-1 being separately positive(or zero) and negative.


For the case {{{2x-1>=0}}}, 
|2x-1|=2x-1.


For the case {{{2x-1<0}}}, 
|2x-1|=-(2x-1)=1-2x.


Do you know what to do now?