Question 841877
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Hi
3x^2+8x+2k=0  |ax^2 + bx + c = 0, where c = 2k
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
{{{x = (-16 +- sqrt( 64-24k)))/6 }}}
2 different negative real number solutions &#8658;
   0 < 64-24k < 256
  -64 < -24k < 192
   64/24 > k > -8
    -8 < k < 8/3