Question 841778
<pre><font face = "Tohoma" size = 3 color = "indigo"><b> 
Hi,
the standard slope-intercept form for an equation of a line is {{{y = green(m)x + b}}}
  where m is the slope and b the y-intercept.

find the equation of a line that contains the point (-4,2) 
and is parallel to the line 3x + 4y=4
First: find slope of 3x + 4y=4 :    y = {{{highlight(-3/4)x + 1}}}, (Green Line)
New line parallel to that line(same slope):
 y = {{{highlight(-3/4)x +b}}},    |Using P(-4,2) to solve for b
 2 = (-3/4)(-4) + b
 2 - 3 = b
-1= b
 y = {{{highlight (-3/4)x -1  }}} Blue Line
 {{{drawing(300,300,   -6, 6, -6, 6, grid(1), 
circle(-4, 2,0.2),
graph( 300, 300, -6, 6, -6, 6,0,(-3/4)x +1,(-3/4)x -1))}}}