Question 841048
let the second number be x and first number = 2x-1
{{{(2x-1)^2+x^2 = 34}}}
{{{4x^2-4x +1 +x^2 -34 = 0}}}
{{{5x^2 -4x-33=0)}}}
{{{5x^2-15x + 11x-33=0}}}
{{{5x(x-3)+11(x-3)=0}}}
{{{(5x+11)(x-3)=0}}}
x=3
therefore the numbers are 5,3