Question 841319
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Hi,
<u>POISSON Distribution</u> 
P(x; &#956;) = {{{e^(-mu)((mu)^x)/x!}}}   where  &#956;  is the average number of successes  
P(x = 0) = {{{e^(-1.8)((1.8)^0)/0!= .1653}}}  16.53% 
0r TI:  poissonpdf(mean, x-value)= poissonpdf(1.8,0)