Question 841326
Let the shortest side be x ,
then Hypotenuse = 2x-1 and other side = x+1
By Pythagoras theorem,

{{{(2x-1)^2 = (x+1)^2 + x^2}}}
{{{4x^2 -8x +1 = x^2+1+2x +x^2}}}
{{{2x^2 -6x = 0}}}
2x(x-3)=0
x-3=0
x=3
therefore the side of the triange are x,x+1, 2x-1 => 3,4,5