Question 841165
{{{7b^2-112=0}}}


{{{7b^2=112}}}


{{{b^2=112/7}}}


{{{b^2=16}}}


{{{b=""+-sqrt(16)}}}


{{{b=sqrt(16)}}} or {{{b=-sqrt(16)}}}


{{{b=4}}} or {{{b=-4}}}



The two solutions are: {{{b=4}}} or {{{b=-4}}}