Question 840864
{{{drawing(425,250,-4,13,-0.35,9.65,
line(0,0,-3.75,9.27),line(0,0,12,0),
line(-3.75,9.27,8.25,9.27),line(12,0,8.25,9.27),
locate(0,1,112^o),locate(-3.5,9.2,2x+2),locate(11.3,0.8,y)
)}}} I believe this is your parallelogram.
It is not a rectangle, because a rectangle is a parallelogram with four {{{90^o}}} angles, and this parallelogram has a {{{112^o}}} angle.
 
In a parallelogram,
opposite angles are congruent (same measure), and
adjacent angles are supplementary (their measures add up to {{{180^o}}}.
So,
{{{y=2x+2=180^o-112^o=68^o}}}
{{{highlight(y=68)}}}
and {{{2x+2=68}}}-->{{{2x=68-2}}}-->{{{2x=66}}}-->{{{x=66/2}}}-->{{{highlight(x=33)}}}