Question 841097
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Hi,
Note:{{{log(a, (p)) = log(b,p)/log(b, (a)) }}}
{{{log(2, (23)) = log(10,23)/ log(10, (2)) }}}
{{{log(3, (32)) = log(10,32)/ log(10, (3)) }}}
3){{{ 5^(2x)- 7(5^x) + 10 = 0}}}   Let {{{y = 5^x}}}
  y^2 - 7y + 10 = 0
 (y-5)(y-2) = 0,  y = 5   0r   y = 2
{{{y = 5^x}}}
 log(5)/log(5) = x
 log(2)/log(5) = x