Question 840986
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Hi,
{{{1/(3m^2n^4/9m^3n)^2 = 1/((3m^2n^4)^2 /(9m^3n)^2) = (9m^3n)^2/(3m^2n^4)^2 = 81m^6n^2/(9m^4n^8) = 9m^2n^(-6) }}}
{{{a^0 = 1}}}
{{{(a^p)^q = a^(p*q)}}}
{{{x^m/x^n=x^(m-n)}}}
{{{( x^m )( x^n ) = x^( m + n )}}}
{{{(xy)^n = x^n*y^n}}}