Question 840983
The closest distance of a point to a line is a perpendicular line through that point.
Perpendicular slopes have the relationship,
{{{m[1]*m[2]=-1}}}
{{{2*m[2]=-1}}}
{{{m{2]=-1/2}}}
{{{y=-(1/2)x+b }}}
Use the point to solve for {{{b}}}
{{{-4=-(1/2)(5)+b}}}
{{{b=-8/2+5/2}}}
{{{b=-3/2}}}
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{{{y=-(1/2)x-3/2}}}
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{{{drawing(300,300,-6,6,-6,6,grid(1),circle(5,-4,0.2),
graph(300,300,-6,6,-6,6,2x-4,-(1/2)x-3/2))}}}