<PRE><B>Question 70905</B>
Let number of nickels be N
number of dimes be D
number of quarters be Q
By the conditions of the problem
D= 2Q
Q = N + 11

The value of the coins is .05N + .1D + .25Q = 5.45

We have N = Q - 11

Substitute into equation for value of coins

  .05(Q - 11) + .2Q + .25Q = 5.45

 Solving for Q gives Q = 12

  Then N = Q - 11
         = 1

 D = 2Q

   = 24

 1 nickel, 24 dimes , 12 quarters</PRE>