Question 840799
Use a substitution,
{{{u=(x-2)^(1/3)}}} 
then
{{{u^2=(x-2)^(2/3)}}}
.
.
.
{{{u^2+u-20=0}}}
{{{(u+5)(u-4)=0}}}
Two possible solutions:
{{{u+5=0}}}
{{{u=-5}}}
{{{(x-2)^(1/3)=-5}}}
Not defined, not a solution.
.
.
{{{u-4=0}}}
{{{u=4}}}
{{{(x-2)^(1/3)=4}}}
{{{x-2=64}}}
{{{x=66}}}