Question 70884
The standard form of an equation is:
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{{{Ax + By = C}}}
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The equation you were given is:
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{{{y+11=(1/3)*(x+3)}}}
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One of the first things we can do is to get rid of the denominator of the fraction on the
right side. We do this by multiplying all terms on both the left and right side of the equation
by 3. On the right side when you multiply 3 times {{{1/3}}} the result is {{{3/3}}}
which just becomes {{{1}}} and multiplying that {{{1}}} by ({{{x+3}}} results in the whole
right side being reduced to {{{x+3}}}.  Multiplying the {{{y+11}}} on the left side 
results in the left side becomes {{{3y + 33}}}. So the problem is now in the form:
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{{{3y + 33 = x + 3}}}
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Now look at the standard form.  The terms containing the letter variables x and y are
alone on the left side and the constants are combined on the right side.  So now let's
get both the lettered terms on the left side.  To do that we need to get rid of the x
on the right side of the equation.  We do that by subtracting x from the right side.
But if we do that we also have to subtract x from the right side.  When we do that the
equation becomes:
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{{{-x + 3y + 33 = 3}}}
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We are getting closer to the standard form.  Now notice that we have a 33 on the left
side, but this is a constant and we need to have all the constants lumped together 
on the right side. So let's subtract 33 from the left side.  To do that we also need to
subtract 33 from the right side. After we do that the resulting equation is:
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{{{-x + 3y + -30}}}
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That's it. Compare this to the standard form that was given at the start of this response 
and you will notice that they are both in the same form.
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Hope this helps you to understand the standard form a little better and how to move
things around in an equation to get that equation into standard form.