Question 840729
Given that tan theta = - (55)^(1/2)/5
the opposite side = (55)^(1/2) 
adjacent side = -5 (since the condition given is cosine theta is < 0)
hypotenuse = square root of ( ((55)^(1/2))^2 + (-5)^2)
= Square root of (55 + 25)
=square root of (80)
= 4 *(5)^(1/2)

Sine theta = square root of (55)/ 4*square root of (5)
= square root(5)*square root(11)/4* Square root(5)
=square root(11)/4