Question 840779


Let {{{c}}} be the {{{longest}}} side on given set of three numbers.

given:

{{{c=6}}}
{{{a=4}}}
{{{b=5}}]


 If {{{c^2 = a^2+b^2}}}, the triangle is {{{right}}}

{{{6^2 = 4^2+5^2}}}
 
{{{36 = 16+25}}} 

{{{36 <> 41}}} ..............so, the triangle is NOT {{{right}}}



 If {{{c^2 > a^2 + b^2}}}, the triangle is {{{obtuse}}}

{{{36 > 41}}}......NOT TRUE; so the triangle is NOT {{{obtuse}}}


 If {{{c^2 < a^2 + b^2}}}, the triangle is {{{acute}}}.

{{{36 < 41}}}......TRUE; so,the triangle IS {{{acute}}}