Question 70838
{{{(cross(x^3)*y^2)/cross(x^3)=(t^4/w)/x^3}}}Divide both sides by {{{x^3}}}
{{{y^2=(t^4/w)*(1/x^3)}}}When dividing fractions invert the divisor (the bottom most term, in this case {{{x^3}}} goes to {{{1/x^3}}})
{{{y^2=t^4/(w*x^3)}}}Multiply fractions
{{{sqrt(y^2)=sqrt(t^4/(w*x^3))}}}
{{{y=0+-sqrt(t^4/(w*x^3))}}}You can further simplify, but it is finally in y form (ignore the 0 in front)