Question 840447
{{{f(x)=-2x^2+3x+1}}}
{{{f(2)=-2(2)^2+3(2)+1=-8+6+1=-1}}}
{{{f(2+h)=-2(2+h)^2+3(2+h)+1=-2(4+4h+h^2)+6+3h+1=-8-8h-2h^2+3h+7=-2h^2-5h-1}}}
{{{f(2+h)-f(2)=-2h^2-8h-1+1=-2h^2-5h}}}
{{{(f(2+h)-f(2))/h=-2h-5}}}