Question 840551
lets write it differently shall we.

there are 10 committee members, so lets number them as committee member numbers 1,2,3,4,5,6,7,8,9,10

we want seven. First of all there are a few very important things to note about the question.
1. Order is not important. I need to choose 7 members, not 7 consecutive members but any 7 from 10. From that we can deduce that this is a combinatorics problem of type n choose k where n = size of the larger set and k = the size of each combination

n choose k is found by calculating the binomial coefficient found using the formula

n!/k!(n-k)! thus our answer is 10!/7!(10-7)! = 120 combinations of 7 committee members

ref: http://en.wikipedia.org/wiki/Combination
useful link: combinatorics and permutation calculator -http://www.mathsisfun.com/combinatorics/combinations-permutations-calculator.html