Question 840416
{{{y=10 f(x-11)+32}}}


Inverse wanted:  {{{x=10f(y-11)+32}}}, and solve for y.
{{{10fy-110f+32=x}}}
{{{10fy=110f-32+x}}}
{{{y=(110f-32+x)/(10f)}}}, the inverse.  Really, the inverse should now be named something other than y.