<PRE><B>Question 840421</B>
A family has 8 girls and 4 boys. A total of 3 children must be chose to speak on the behalf of the family at a local benefit. What is the probability that no girls and 3 boys will be chosen? 
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# of ways to succeed: 4C3 = 4
# of random triples: 8C3 = (8*7*6)/(1*2*3) = 56
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P(3 boys chosen) = 4/56 = 1/14
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Cheers,
Stan H.
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