Question 840235
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Hi,

{{{log(3,x)-log (3,(x-5)) = 1}}} &#8658;
{{{log(3, x/(x-5)) = log(3,3)}}}  Note:  {{{1 = log(3,3)}}}
0r
  {{{x/(x-5) = 3}}}
    x = 3(x-5)
    x = 3x - 15
    15 = 2x
   15/2 = x     0r    x =  7 <sup>1</sup>&frasl;<sub>2</sub>