Question 840157
<pre>
y = 4|x| + 2

To find the x-intercept (if there is one) we substitute 0 for y:

0 = 4|x| + 2

Solve for |x|, add -2 to both sides:

-2 = 4|x|

Divide both sides by 4

{{{-2/4}}} = |x|

{{{-1/2}}} = |x|

The absolute value of a number can never be negative.

therefore there can be no x-intercept.

The graph also shows why there can be no x-intercept,
because we get this V-shaped graph which never 
gets down to the x-axis to intersect it. 

{{{graph(400,240,-10,10,-2,10,4abs(x)+2)}}}

Edwin</pre>