Question 839553
{{{3x^2 + 4x - 2 = 0}}}
The quadratic formula works with the coefficients
for an equation of the format
{{{ax^2+bx+c=0}}}
For our equation, a = 3, b = 4, and c = -2
The quadratic equation is
{{{(-b + sqrt(b^2-4ac))/(2a)}}} or {{{(-b - sqrt(b^2-4ac))/(2a)}}}
Working first with {{{(-b + sqrt(b^2-4ac))/(2a)}}}
{{{(-(4) + sqrt( (4)^2 -4(3)(-2)) )/(2(3))}}}
{{{(-4 + sqrt( 16 + 24 ) )/6)}}}
{{{(-4 + sqrt( 40 ) )/6)}}}
{{{(-4 + 2*sqrt( 10 ) )/6)}}}

{{{(-2 + sqrt( 10 ) )/3)}}}
Working with {{{(-b - sqrt(b^2-4ac))/(2a)}}} will give us
{{{(-2 - sqrt( 10 ) )/3)}}}