Question 839425
If you have three squares each having an area of 10 cm^2, they form a triangle by touching corners what is the area of the triangle
:
{{{sqrt(10)}}} = the side of the square and the sides of the equilateral triangles formed by the 3 squares
:
Find the altitude of the triangle, (a) 
This is an equilateral triangle all angles = 60 degrees
Use the sine of 60 to find the altitude
sin(60) = {{{a/sqrt(10)}}}
a = 2.74 is the altitude of the triangle
A = {{{1/2}}}*{{{sqrt(10) * 2.74}}}
A = 4.33 sq/cm