Question 839258
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Hi,
three consecutive positive odd integers:{{{highlight_green(x)}}},{{{highlight_green(x+2)}}},{{{highlight_green(x+4)}}}
Question states***product of the first and third is equal to one less then twice the second
***  x(x+4) = 2(x+2) - 1
    x^2 + 2x -3 = 0
   (x + 3)(x - 1) = 0,   x  = 1 (<u>positive odd integers</u>)
The three consecutive positive odd integers are:  1, 3,  5
CHECKING our answer***
 {{{1*5 = 2*3 - 1 = 5}}}
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