Question 839220
I'm thinking you need to solve for {{{f(25)}}} when {{{f(x)=500e^(0.04x)}}}
{{{f(25)=500e^(0.04(25))}}}
{{{f(25)=500e^1}}}
{{{f(25)=500e}}} or approximately 
{{{f(25)=500(2.718)}}}
{{{f(25)=1359.1}}}