Question 839083
Perpendicular line would have form, {{{x-3y=D}}}
Use the point to solve for {{{D}}}.
{{{0-3(-4)=D}}}
{{{D=12}}}
{{{x-3y=12}}}
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{{{drawing(300,300,-10,10,-10,10,grid(1),circle(0,-4,0.5),
graph(300,300,-10,10,-10,10,12-3x,(12-x)/(-3)))}}}