Question 839002
Let {{{ a }}} = amount charged by 1st mechanic
Let {{{ b }}} = amount charged by 2nd mechanic
Let {{{ a/15 }}} = the rate for the 1st mechanic
Let {{{ b/5 }}} = the rate for the 2nd mechanic
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(1) {{{ a + b = 1750 }}}
(2) {{{ a/15 + b/5 = 160/1 }}}  dollars/hr
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Multiply both sides of (2) by {{{ 15 }}}
(2) {{{ a + 3b = 2400 }}}
Subtract (1) from (2)
(2) {{{ a + 3b = 2400 }}}
(1) {{{ -a - b = -1750 }}}
{{{ 2b = 650 }}}
{{{ b = 325 }}}
and, since
(1) {{{ a + b = 1750 }}}
(1) {{{ a = 1750 - b }}}
(1) {{{ a = 1425 }}}
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The 1st mechanic's rate is:
{{{ 1425/15 = 95 }}}
$95/hr
The 2nd mechanic's rate is:
{{{ 325/5 = 65 }}}
$65/hr
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check:
(1) {{{ a + b = 1750 }}}
(1) {{{ 1425 + 325 = 1750 }}}
(1) {{{ 1750 = 1750 }}}
OK