Question 838995
Let the integers be {{{ n }}}, {{{ n+1 }}}, and {{{ n + 2 }}}
{{{ 4*( n+2 ) = 3*( n + n + 1 ) - 51 }}}
{{{ 4n + 8 = 3*( 2n + 1 ) - 51 }}}
{{{ 4n = 6n + 3 - 51 - 8 }}}
{{{ 4n = 6n - 56 }}}
{{{ 6n - 4n = 56 }}}
{{{ 2n = 56 }}}
{{{ n = 28 }}}
{{{ n + 1 = 29 }}}
{{{ n + 2 = 30 }}}
The 3rd integer is 30
check:
{{{ 4*( n+2 ) = 3*( n + n + 1 ) - 51 }}}
{{{ 4*( 30 ) = 3*( 28 + 29 ) - 51 }}}
{{{ 120 = 3*57 - 51 }}}
{{{ 120 = 171 - 51 }}}
{{{ 120 = 120 }}}
OK