Question 838173
{{{x}}}= length, in feet, of the side opposite the {{{30^o}}} angle
{{{sin(30^o)=opposite_side/hypotenuse}}}
{{{sin(30^o)=0.5}}}
{{{hypotenuse=20ft}}}
So, {{{0.5=x/20}}} --> {{{x=0.5*20}}} --> {{{x=10}}}
{{{y}}}= length, in feet, of the side adjacent to the {{{30^o}}} angle
{{{cos(30^o)=adjacent_side/hypotenuse}}}
{{{cos(30^o)=sqrt(3)/2=approximately}}}{{{0.866}}}
So, {{{sqrt3)/2=y/20}}} --> {{{y=20sqrt(3)/2}}} --> {{{y=10sqrt(3)}}}
{{{y=approximately}}}{{{17.32}}}