Question 838670
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Hi,
Recommend Sketching initially:vertex at (0, 0) and a directrix y = -1
Then using the general format to determine the equation:  {{{y = (1/4)x^2}}}
the vertex form of a Parabola opening up(a>0) or down(a<0), {{{y=a(x-h)^2 +k}}} 
where(h,k) is the vertex  and  x = h  is the Line of Symmetry
The standard form is {{{(x -h)^2 = 4p(y -k)}}}, where  the focus is (h,k + p)
and directrix is  y = -(h+p)


{{{drawing(300,300,   -6, 6, -6, 6, grid(1), 
circle(0, 0,0.2),
circle(0, 1,0.2),

graph( 300, 300, -6, 6, -6, 6,0,-1, .25x^2 ))}}}