Question 838609
{{{x^2(x^2-16)=0}}}
{{{x^2(x+4)(x-4)=0}}}
Three solutions:
{{{x^2=0}}}
{{{x=0}}}, 2
and
{{{x-4=0}}}
{{{x=4}}}, 1
and
{{{x+4=0}}}
{{{x=-4}}}, 1