Question 838298
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Hi,
How many liters of water must be added to 10 liters of a 36% soap solution (64% water) 
to make it a 12% soap solution (88% water)?
Let x represent the liters of water added
          water = water
 {{{.64*10 + x = .88(10+x)}}}
 {{{.12x = .24*10}}}
     {{{x = (.24*10)/.12 }}}  x = 20L of water must be added