Question 838062
Let {{{A}}} be the smaller number, {{{B}}} the larger number.
1.{{{B=A+5}}} The larger number is 5 more than the smaller number
2.{{{2*B=3A-12}}} "twice the larger is 12 less than 3 times the smaller"
Substitute eq. 1 into eq. 2,
{{{2(A+5)=3A-12}}}
{{{2A+10=3A-12}}}
{{{A=22}}}
Then use either equation to solve for {{{B}}},
{{{B=22+5}}}
{{{B=27}}}