Question 838055
In general {{{log(a, (p))=n}}} is equivalent to {{{p = a^n}}}. The hardest part of these problems is just knowing that ln is a log and that its base is "e".<br>
So ln(x+4)=8 becomes {{{x+4=e^8}}} and ln(x-6)=5 becomes {{{x-6 = e^5}}}