Question 838170
{{{27^(n-1) = 3^6}}}
(n-1)*log(27) = 6log(3)
n-1 = 6log(3)/log(27)
n = 1 + 6log(3)/log(27)
Using a calculator
n = 1 + 2
n = 3
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If you know
{{{27 = 3^3}}}
{{{27^(n-1) = 3^6}}}
{{{3^(3(n-1)) = 3^6}}}
3(n-1) = 6
n-1 = 2
n = 3