Question 838110

Hello, I need your guys help, and I'm sorry if I'm in the wrong place!

Ok, the problem is this: 2d = 3/2d +9. 

In the book, it changed that problem into this...4d = 3d + 18. I'm having trouble figuring out how did 2d=3/2d+9 turn into 4d=3d+18. 

The only way I can think of is to multiply everything by 2, but why??? Wouldn't the first step to this problem is to put "d" by it self or something? I already know what to do with "4d=3d+18" to get an answer. The only thing I'm having trouble is how did 2d=3/2d+9 turn into 4d=3d+18<pre>
The best way to approach this problem is to ELIMINATE the fraction, {{{(3/2)d}}}. We began with: {{{2d = (3/2)d + 9}}}
{{{2(2d) = 2(3/2)d + 2(9)}}} ------- Multiplying both sides by 2 to get rid of the fraction, {{{(3/2)d}}}
{{{4d = cross(2)(3/cross(2))d + 18}}}
4d = 3d + 18
Now you should be able to solve for d
Then do a check!! 

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